Solve for y (3(y+7))/(7y)-(4y-7)/6=(7y+10)/(3y)-(2(7y-1))/21

$\frac{3 (y + 7)}{7 y} - \frac{4 y - 7}{6} = \frac{7 y + 10}{3 y} - \frac{2 (7 y - 1)}{21}$

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$7 y, 6, 3 y, 21$

Since $7 y, 6, 3 y, 21$ contain both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $7, 6, 3, 21$ then find LCM for the variable part $y^{1}, y^{1}$ .

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

Since $7$ has no factors besides $1$ and $7$ .

$7$ is a prime number

$6$ has factors of $2$ and $3$ .

$2 \cdot 3$

Since $3$ has no factors besides $1$ and $3$ .

$3$ is a prime number

$21$ has factors of $3$ and $7$ .

$3 \cdot 7$

The LCM of $7, 6, 3, 21$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$2 \cdot 3 \cdot 7$

The LCM of $7, 6, 3, 21$ is $2 \cdot 3 \cdot 7 = 42$ .

Multiply $2$ by $3$ .

$6 \cdot 7$

Multiply $6$ by $7$ .

$42$

The factor for $y^{1}$ is $y$ itself.

$y^{1} = y$

$y$ occurs $1$ time.

The LCM of $y^{1}, y^{1}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$y$

The LCM for $7 y, 6, 3 y, 21$ is the numeric part $42$ multiplied by the variable part.

$42 y$

Multiply each term in $\frac{3 (y + 7)}{7 y} - \frac{4 y - 7}{6} = \frac{7 y + 10}{3 y} - \frac{2 (7 y - 1)}{21}$ by $42 y$ to eliminate the fractions.

Multiply each term in $\frac{3 (y + 7)}{7 y} - \frac{4 y - 7}{6} = \frac{7 y + 10}{3 y} - \frac{2 (7 y - 1)}{21}$ by $42 y$ .

$\frac{3 (y + 7)}{7 y} (42 y) - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Simplify the left side.

Simplify each term.

Rewrite using the commutative property of multiplication.

$42 \frac{3 (y + 7)}{7 y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor of $7$ .

Factor $7$ out of $42$ .

$7 (6) \frac{3 (y + 7)}{7 y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Factor $7$ out of $7 y$ .

$7 (6) \frac{3 (y + 7)}{7 (y)} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor.

$7 \cdot 6 \frac{3 (y + 7)}{7 y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Rewrite the expression.

$6 \frac{3 (y + 7)}{y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Combine $6$ and $\frac{3 (y + 7)}{y}$ .

$\frac{6 (3 (y + 7))}{y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $3$ by $6$ .

$\frac{18 (y + 7)}{y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor of $y$ .

Cancel the common factor.

$\frac{18 (y + 7)}{y} y - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Rewrite the expression.

$18 (y + 7) - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Apply the distributive property.

$18 y + 18 \cdot 7 - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $18$ by $7$ .

$18 y + 126 - \frac{4 y - 7}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor of $6$ .

Move the leading negative in $- \frac{4 y - 7}{6}$ into the numerator.

$18 y + 126 + \frac{- (4 y - 7)}{6} (42 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Factor $6$ out of $42 y$ .

$18 y + 126 + \frac{- (4 y - 7)}{6} (6 (7 y)) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor.

$18 y + 126 + \frac{- (4 y - 7)}{6} (6 (7 y)) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Rewrite the expression.

$18 y + 126 - (4 y - 7) (7 y) = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $7$ by $- 1$ .

$18 y + 126 - 7 (4 y - 7) y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Apply the distributive property.

$18 y + 126 + (- 7 (4 y) - 7 \cdot - 7) y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $4$ by $- 7$ .

$18 y + 126 + (- 28 y - 7 \cdot - 7) y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $- 7$ by $- 7$ .

$18 y + 126 + (- 28 y + 49) y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Apply the distributive property.

$18 y + 126 - 28 y \cdot y + 49 y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $y$ by $y$ by adding the exponents.

Move $y$ .

$18 y + 126 - 28 (y \cdot y) + 49 y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $y$ by $y$ .

$18 y + 126 - 28 y^{2} + 49 y = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Add $18 y$ and $49 y$ .

$67 y + 126 - 28 y^{2} = \frac{7 y + 10}{3 y} (42 y) - \frac{2 (7 y - 1)}{21} (42 y)$

Simplify the right side.

Simplify each term.

Rewrite using the commutative property of multiplication.

$67 y + 126 - 28 y^{2} = 42 \frac{7 y + 10}{3 y} y - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor of $3$ .

Factor $3$ out of $42$ .

$67 y + 126 - 28 y^{2} = 3 (14) \frac{7 y + 10}{3 y} y - \frac{2 (7 y - 1)}{21} (42 y)$

Factor $3$ out of $3 y$ .

$67 y + 126 - 28 y^{2} = 3 (14) \frac{7 y + 10}{3 (y)} y - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor.

$67 y + 126 - 28 y^{2} = 3 \cdot 14 \frac{7 y + 10}{3 y} y - \frac{2 (7 y - 1)}{21} (42 y)$

Rewrite the expression.

$67 y + 126 - 28 y^{2} = 14 \frac{7 y + 10}{y} y - \frac{2 (7 y - 1)}{21} (42 y)$

Combine $14$ and $\frac{7 y + 10}{y}$ .

$67 y + 126 - 28 y^{2} = \frac{14 (7 y + 10)}{y} y - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor of $y$ .

Cancel the common factor.

$67 y + 126 - 28 y^{2} = \frac{14 (7 y + 10)}{y} y - \frac{2 (7 y - 1)}{21} (42 y)$

Rewrite the expression.

$67 y + 126 - 28 y^{2} = 14 (7 y + 10) - \frac{2 (7 y - 1)}{21} (42 y)$

Apply the distributive property.

$67 y + 126 - 28 y^{2} = 14 (7 y) + 14 \cdot 10 - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $7$ by $14$ .

$67 y + 126 - 28 y^{2} = 98 y + 14 \cdot 10 - \frac{2 (7 y - 1)}{21} (42 y)$

Multiply $14$ by $10$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 - \frac{2 (7 y - 1)}{21} (42 y)$

Cancel the common factor of $21$ .

Move the leading negative in $- \frac{2 (7 y - 1)}{21}$ into the numerator.

$67 y + 126 - 28 y^{2} = 98 y + 140 + \frac{- 2 (7 y - 1)}{21} (42 y)$

Factor $21$ out of $42 y$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 + \frac{- 2 (7 y - 1)}{21} (21 (2 y))$

Cancel the common factor.

$67 y + 126 - 28 y^{2} = 98 y + 140 + \frac{- 2 (7 y - 1)}{21} (21 (2 y))$

Rewrite the expression.

$67 y + 126 - 28 y^{2} = 98 y + 140 - 2 (7 y - 1) (2 y)$

Multiply $2$ by $- 2$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 - 4 (7 y - 1) y$

Apply the distributive property.

$67 y + 126 - 28 y^{2} = 98 y + 140 + (- 4 (7 y) - 4 \cdot - 1) y$

Multiply $7$ by $- 4$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 + (- 28 y - 4 \cdot - 1) y$

Multiply $- 4$ by $- 1$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 + (- 28 y + 4) y$

Apply the distributive property.

$67 y + 126 - 28 y^{2} = 98 y + 140 - 28 y \cdot y + 4 y$

Multiply $y$ by $y$ by adding the exponents.

Move $y$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 - 28 (y \cdot y) + 4 y$

Multiply $y$ by $y$ .

$67 y + 126 - 28 y^{2} = 98 y + 140 - 28 y^{2} + 4 y$

Add $98 y$ and $4 y$ .

$67 y + 126 - 28 y^{2} = 102 y + 140 - 28 y^{2}$

Solve the equation.

Move all terms containing $y$ to the left side of the equation.

Subtract $102 y$ from both sides of the equation.

$67 y + 126 - 28 y^{2} - 102 y = 140 - 28 y^{2}$

Add $28 y^{2}$ to both sides of the equation.

$67 y + 126 - 28 y^{2} - 102 y + 28 y^{2} = 140$

Combine the opposite terms in $67 y + 126 - 28 y^{2} - 102 y + 28 y^{2}$ .

Add $- 28 y^{2}$ and $28 y^{2}$ .

$67 y + 126 - 102 y + 0 = 140$

Add $67 y + 126 - 102 y$ and $0$ .

$67 y + 126 - 102 y = 140$

Subtract $102 y$ from $67 y$ .

$- 35 y + 126 = 140$

Move all terms not containing $y$ to the right side of the equation.

Subtract $126$ from both sides of the equation.

$- 35 y = 140 - 126$

Subtract $126$ from $140$ .

$- 35 y = 14$

Divide each term in $- 35 y = 14$ by $- 35$ and simplify.

Divide each term in $- 35 y = 14$ by $- 35$ .

$\frac{- 35 y}{- 35} = \frac{14}{- 35}$

Simplify the left side.

Cancel the common factor of $- 35$ .

Cancel the common factor.

$\frac{- 35 y}{- 35} = \frac{14}{- 35}$

Divide $y$ by $1$ .

$y = \frac{14}{- 35}$

Simplify the right side.

Cancel the common factor of $14$ and $- 35$ .

Factor $7$ out of $14$ .

$y = \frac{7 (2)}{- 35}$

Cancel the common factors.

Factor $7$ out of $- 35$ .

$y = \frac{7 \cdot 2}{7 \cdot - 5}$

Cancel the common factor.

$y = \frac{7 \cdot 2}{7 \cdot - 5}$

Rewrite the expression.

$y = \frac{2}{- 5}$

Move the negative in front of the fraction.

$y = - \frac{2}{5}$

The result can be shown in multiple forms.

Exact Form:

$y = - \frac{2}{5}$

Decimal Form:

$y = - 0.4$

Solve for y (3(y+7))/(7y)-(4y-7)/6=(7y+10)/(3y)-(2(7y-1))/21

Related Questions

Support LCMGCF.com by disabling your adblocker.