Solve for y 3x-2y=18 for y

$3 x - 2 y = 18$ for $y$

Step 1

Subtract $3 x$ from both sides of the equation.

$- 2 y = 18 - 3 x$

Step 2

Divide each term in $- 2 y = 18 - 3 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = 18 - 3 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{18}{- 2} + \frac{- 3 x}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{18}{- 2} + \frac{- 3 x}{- 2}$

Divide $y$ by $1$ .

$y = \frac{18}{- 2} + \frac{- 3 x}{- 2}$

Simplify the right side.

Simplify each term.

Divide $18$ by $- 2$ .

$y = - 9 + \frac{- 3 x}{- 2}$

Dividing two negative values results in a positive value.

$y = - 9 + \frac{3 x}{2}$