Solve for y 3x+9y=27

$3 x + 9 y = 27$

Step 1

Subtract $3 x$ from both sides of the equation.

$9 y = 27 - 3 x$

Step 2

Divide each term in $9 y = 27 - 3 x$ by $9$ and simplify.

Divide each term in $9 y = 27 - 3 x$ by $9$ .

$\frac{9 y}{9} = \frac{27}{9} + \frac{- 3 x}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 y}{9} = \frac{27}{9} + \frac{- 3 x}{9}$

Divide $y$ by $1$ .

$y = \frac{27}{9} + \frac{- 3 x}{9}$

$y = \frac{27}{9} + \frac{- 3 x}{9}$

$y = \frac{27}{9} + \frac{- 3 x}{9}$

Simplify the right side.

Simplify each term.

Divide $27$ by $9$ .

$y = 3 + \frac{- 3 x}{9}$

Cancel the common factor of $- 3$ and $9$ .

Factor $3$ out of $- 3 x$ .

$y = 3 + \frac{3 (- x)}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$y = 3 + \frac{3 (- x)}{3 (3)}$

Cancel the common factor.

$y = 3 + \frac{3 (- x)}{3 \cdot 3}$

Rewrite the expression.

$y = 3 + \frac{- x}{3}$

$y = 3 + \frac{- x}{3}$

$y = 3 + \frac{- x}{3}$

Move the negative in front of the fraction.

$y = 3 - \frac{x}{3}$

$y = 3 - \frac{x}{3}$

$y = 3 - \frac{x}{3}$

$y = 3 - \frac{x}{3}$

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