Solve for y 3y+20=3+2y

$3 y + 20 = 3 + 2 y$

Step 1

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$3 y + 20 - 2 y = 3$

Subtract $2 y$ from $3 y$ .

$y + 20 = 3$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Subtract $20$ from both sides of the equation.

$y = 3 - 20$

Subtract $20$ from $3$ .

$y = - 17$