Solve for y 3y=4y-4x

$3 y = 4 y - 4 x$

Step 1

Move all terms containing $y$ to the left side of the equation.

Subtract $4 y$ from both sides of the equation.

$3 y - 4 y = - 4 x$

Subtract $4 y$ from $3 y$ .

$- y = - 4 x$

Step 2

Divide each term in $- y = - 4 x$ by $- 1$ and simplify.

Divide each term in $- y = - 4 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 4 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 4 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 4 x}{- 1}$

Simplify the right side.

Move the negative one from the denominator of $\frac{- 4 x}{- 1}$ .

$y = - 1 \cdot (- 4 x)$

Rewrite $- 1 \cdot (- 4 x)$ as $- (- 4 x)$ .

$y = - (- 4 x)$

Multiply $- 4$ by $- 1$ .

$y = 4 x$