Solve for y (3y-6)/(2y)=17/3

$\frac{3 y - 6}{2 y} = \frac{17}{3}$

Factor $3$ out of $3 y - 6$ .

Factor $3$ out of $3 y$ .

$\frac{3 (y) - 6}{2 y} = \frac{17}{3}$

Factor $3$ out of $- 6$ .

$\frac{3 y + 3 \cdot - 2}{2 y} = \frac{17}{3}$

Factor $3$ out of $3 y + 3 \cdot - 2$ .

$\frac{3 (y - 2)}{2 y} = \frac{17}{3}$

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$3 (y - 2) \cdot 3 = 2 y \cdot 17$

Solve the equation for $y$ .

Simplify $3 (y - 2) \cdot 3$ .

Start simplifying.

$0 + 0 + 3 (y - 2) \cdot 3 = 2 y \cdot 17$

Simplify by adding zeros.

$3 (y - 2) \cdot 3 = 2 y \cdot 17$

Apply the distributive property.

$(3 y + 3 \cdot - 2) \cdot 3 = 2 y \cdot 17$

Multiply $3$ by $- 2$ .

$(3 y - 6) \cdot 3 = 2 y \cdot 17$

Apply the distributive property.

$3 y \cdot 3 - 6 \cdot 3 = 2 y \cdot 17$

Multiply.

Multiply $3$ by $3$ .

$9 y - 6 \cdot 3 = 2 y \cdot 17$

Multiply $- 6$ by $3$ .

$9 y - 18 = 2 y \cdot 17$

Multiply $17$ by $2$ .

$9 y - 18 = 34 y$

Move all terms containing $y$ to the left side of the equation.

Subtract $34 y$ from both sides of the equation.

$9 y - 18 - 34 y = 0$

Subtract $34 y$ from $9 y$ .

$- 25 y - 18 = 0$

Add $18$ to both sides of the equation.

$- 25 y = 18$

Divide each term in $- 25 y = 18$ by $- 25$ and simplify.

Divide each term in $- 25 y = 18$ by $- 25$ .

$\frac{- 25 y}{- 25} = \frac{18}{- 25}$

Simplify the left side.

Cancel the common factor of $- 25$ .

Cancel the common factor.

$\frac{- 25 y}{- 25} = \frac{18}{- 25}$

Divide $y$ by $1$ .

$y = \frac{18}{- 25}$

Simplify the right side.

Move the negative in front of the fraction.

$y = - \frac{18}{25}$

The result can be shown in multiple forms.

Exact Form:

$y = - \frac{18}{25}$

Decimal Form:

$y = - 0.72$

Solve for y (3y-6)/(2y)=17/3

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