Solve for y 3y+6+4y-7=-8

$3 y + 6 + 4 y - 7 = - 8$

Simplify $3 y + 6 + 4 y - 7$ .

Add $3 y$ and $4 y$ .

$7 y + 6 - 7 = - 8$

Subtract $7$ from $6$ .

$7 y - 1 = - 8$

Move all terms not containing $y$ to the right side of the equation.

Add $1$ to both sides of the equation.

$7 y = - 8 + 1$

Add $- 8$ and $1$ .

$7 y = - 7$

Divide each term in $7 y = - 7$ by $7$ and simplify.

Divide each term in $7 y = - 7$ by $7$ .

$\frac{7 y}{7} = \frac{- 7}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 y}{7} = \frac{- 7}{7}$

Divide $y$ by $1$ .

$y = \frac{- 7}{7}$

Simplify the right side.

Divide $- 7$ by $7$ .

$y = - 1$