Solve for y 3y=7+5(y-3)

$3 y = 7 + 5 (y - 3)$

Step 1

Simplify $7 + 5 (y - 3)$ .

Simplify each term.

Apply the distributive property.

$3 y = 7 + 5 y + 5 \cdot - 3$

Multiply $5$ by $- 3$ .

$3 y = 7 + 5 y - 15$

Subtract $15$ from $7$ .

$3 y = 5 y - 8$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $5 y$ from both sides of the equation.

$3 y - 5 y = - 8$

Subtract $5 y$ from $3 y$ .

$- 2 y = - 8$

Step 3

Divide each term in $- 2 y = - 8$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 8$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 2}$

Simplify the right side.

Divide $- 8$ by $- 2$ .

$y = 4$