Solve for y 3y+7-y=5+2y+2

$3 y + 7 - y = 5 + 2 y + 2$

Subtract $y$ from $3 y$ .

$2 y + 7 = 5 + 2 y + 2$

Add $5$ and $2$ .

$2 y + 7 = 2 y + 7$

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$2 y + 7 - 2 y = 7$

Combine the opposite terms in $2 y + 7 - 2 y$ .

Subtract $2 y$ from $2 y$ .

$0 + 7 = 7$

Add $0$ and $7$ .

$7 = 7$

Since $7 = 7$ , the equation will always be true for any value of $y$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$