Solve for y 3y-yz=2z

$3 y - y z = 2 z$

Factor $y$ out of $3 y - y z$ .

Factor $y$ out of $3 y$ .

$y \cdot 3 - y z = 2 z$

Factor $y$ out of $- y z$ .

$y \cdot 3 + y (- 1 z) = 2 z$

Factor $y$ out of $y \cdot 3 + y (- 1 z)$ .

$y (3 - 1 z) = 2 z$

Rewrite $- 1 z$ as $- z$ .

$y (3 - z) = 2 z$

Divide each term in $y (3 - z) = 2 z$ by $3 - z$ and simplify.

Divide each term in $y (3 - z) = 2 z$ by $3 - z$ .

$\frac{y (3 - z)}{3 - z} = \frac{2 z}{3 - z}$

Simplify the left side.

Cancel the common factor of $3 - z$ .

Cancel the common factor.

$\frac{y (3 - z)}{3 - z} = \frac{2 z}{3 - z}$

Divide $y$ by $1$ .

$y = \frac{2 z}{3 - z}$