Solve for y 4(0)-3y=12

$4 (0) - 3 y = 12$

Step 1

Simplify $4 (0) - 3 y$ .

Multiply $4$ by $0$ .

$0 - 3 y = 12$

Subtract $3 y$ from $0$ .

$- 3 y = 12$

Step 2

Divide each term in $- 3 y = 12$ by $- 3$ and simplify.

Divide each term in $- 3 y = 12$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{12}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{12}{- 3}$

Divide $y$ by $1$ .

$y = \frac{12}{- 3}$

Simplify the right side.

Divide $12$ by $- 3$ .

$y = - 4$