Solve for y -4^2+3=2(-4)+y

$- 4^{2} + 3 = 2 (- 4) + y$

Step 1

Rewrite the equation as $2 (- 4) + y = - 4^{2} + 3$ .

$2 (- 4) + y = - 4^{2} + 3$

Step 2

Multiply $2$ by $- 4$ .

$- 8 + y = - 4^{2} + 3$

Step 3

Simplify $- 4^{2} + 3$ .

Simplify each term.

Raise $4$ to the power of $2$ .

$- 8 + y = - 1 \cdot 16 + 3$

Multiply $- 1$ by $16$ .

$- 8 + y = - 16 + 3$

Add $- 16$ and $3$ .

$- 8 + y = - 13$

Step 4

Move all terms not containing $y$ to the right side of the equation.

Add $8$ to both sides of the equation.

$y = - 13 + 8$

Add $- 13$ and $8$ .

$y = - 5$