Solve for y 4-3y=x

$4 - 3 y = x$

Subtract $4$ from both sides of the equation.

$- 3 y = x - 4$

Divide each term in $- 3 y = x - 4$ by $- 3$ and simplify.

Divide each term in $- 3 y = x - 4$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{x}{- 3} + \frac{- 4}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{x}{- 3} + \frac{- 4}{- 3}$

Divide $y$ by $1$ .

$y = \frac{x}{- 3} + \frac{- 4}{- 3}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{x}{3} + \frac{- 4}{- 3}$

Dividing two negative values results in a positive value.

$y = - \frac{x}{3} + \frac{4}{3}$