Solve for y 4(y+2)=32

$4 (y + 2) = 32$

Step 1

Divide each term in $4 (y + 2) = 32$ by $4$ and simplify.

Divide each term in $4 (y + 2) = 32$ by $4$ .

$\frac{4 (y + 2)}{4} = \frac{32}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (y + 2)}{4} = \frac{32}{4}$

Divide $y + 2$ by $1$ .

$y + 2 = \frac{32}{4}$

Simplify the right side.

Divide $32$ by $4$ .

$y + 2 = 8$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$y = 8 - 2$

Subtract $2$ from $8$ .

$y = 6$