Solve for y 4(-y+3)=2(5-y)

$4 (- y + 3) = 2 (5 - y)$

Step 1

Simplify $4 (- y + 3)$ .

Rewrite.

$0 + 0 + 4 (- y + 3) = 2 (5 - y)$

Simplify by adding zeros.

$4 (- y + 3) = 2 (5 - y)$

Apply the distributive property.

$4 (- y) + 4 \cdot 3 = 2 (5 - y)$

Multiply.

Multiply $- 1$ by $4$ .

$- 4 y + 4 \cdot 3 = 2 (5 - y)$

Multiply $4$ by $3$ .

$- 4 y + 12 = 2 (5 - y)$

Step 2

Simplify $2 (5 - y)$ .

Apply the distributive property.

$- 4 y + 12 = 2 \cdot 5 + 2 (- y)$

Multiply.

Multiply $2$ by $5$ .

$- 4 y + 12 = 10 + 2 (- y)$

Multiply $- 1$ by $2$ .

$- 4 y + 12 = 10 - 2 y$

Step 3

Move all terms containing $y$ to the left side of the equation.

Add $2 y$ to both sides of the equation.

$- 4 y + 12 + 2 y = 10$

Add $- 4 y$ and $2 y$ .

$- 2 y + 12 = 10$

Step 4

Move all terms not containing $y$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$- 2 y = 10 - 12$

Subtract $12$ from $10$ .

$- 2 y = - 2$

Step 5

Divide each term in $- 2 y = - 2$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 2$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 2}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 2}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 2}{- 2}$

Simplify the right side.

Divide $- 2$ by $- 2$ .

$y = 1$

Solve for y 4(-y+3)=2(5-y)

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