Solve for y 4(y-7)=2y-38

$4 (y - 7) = 2 y - 38$

Step 1

Simplify $4 (y - 7)$ .

Rewrite.

$0 + 0 + 4 (y - 7) = 2 y - 38$

Simplify by adding zeros.

$4 (y - 7) = 2 y - 38$

Apply the distributive property.

$4 y + 4 \cdot - 7 = 2 y - 38$

Multiply $4$ by $- 7$ .

$4 y - 28 = 2 y - 38$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$4 y - 28 - 2 y = - 38$

Subtract $2 y$ from $4 y$ .

$2 y - 28 = - 38$

Step 3

Move all terms not containing $y$ to the right side of the equation.

Add $28$ to both sides of the equation.

$2 y = - 38 + 28$

Add $- 38$ and $28$ .

$2 y = - 10$

Step 4

Divide each term in $2 y = - 10$ by $2$ and simplify.

Divide each term in $2 y = - 10$ by $2$ .

$\frac{2 y}{2} = \frac{- 10}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 10}{2}$

Divide $y$ by $1$ .

$y = \frac{- 10}{2}$

Simplify the right side.

Divide $- 10$ by $2$ .

$y = - 5$