Solve for y 4x=y^2

$4 x = y^{2}$

Step 1

Rewrite the equation as $y^{2} = 4 x$ .

$y^{2} = 4 x$

Step 2

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{4 x}$

Step 3

Simplify $\pm \sqrt{4 x}$ .

Rewrite $4$ as $2^{2}$ .

$y = \pm \sqrt{2^{2} x}$

Pull terms out from under the radical.

$y = \pm 2 \sqrt{x}$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = 2 \sqrt{x}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 2 \sqrt{x}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 2 \sqrt{x}$

$y = - 2 \sqrt{x}$

$y = 2 \sqrt{x}$

$y = - 2 \sqrt{x}$