Solve for y 4y-12b=3c+2y

$4 y - 12 b = 3 c + 2 y$

Step 1

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$4 y - 12 b - 2 y = 3 c$

Subtract $2 y$ from $4 y$ .

$- 12 b + 2 y = 3 c$

Step 2

Add $12 b$ to both sides of the equation.

$2 y = 3 c + 12 b$

Step 3

Divide each term in $2 y = 3 c + 12 b$ by $2$ and simplify.

Divide each term in $2 y = 3 c + 12 b$ by $2$ .

$\frac{2 y}{2} = \frac{3 c}{2} + \frac{12 b}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{3 c}{2} + \frac{12 b}{2}$

Divide $y$ by $1$ .

$y = \frac{3 c}{2} + \frac{12 b}{2}$

Simplify the right side.

Cancel the common factor of $12$ and $2$ .

Factor $2$ out of $12 b$ .

$y = \frac{3 c}{2} + \frac{2 (6 b)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = \frac{3 c}{2} + \frac{2 (6 b)}{2 (1)}$

Cancel the common factor.

$y = \frac{3 c}{2} + \frac{2 (6 b)}{2 \cdot 1}$

Rewrite the expression.

$y = \frac{3 c}{2} + \frac{6 b}{1}$

Divide $6 b$ by $1$ .

$y = \frac{3 c}{2} + 6 b$