Solve for y 4y+7=3x-8

$4 y + 7 = 3 x - 8$

Step 1

Move all terms not containing $y$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$4 y = 3 x - 8 - 7$

Subtract $7$ from $- 8$ .

$4 y = 3 x - 15$

Step 2

Divide each term in $4 y = 3 x - 15$ by $4$ and simplify.

Divide each term in $4 y = 3 x - 15$ by $4$ .

$\frac{4 y}{4} = \frac{3 x}{4} + \frac{- 15}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{3 x}{4} + \frac{- 15}{4}$

Divide $y$ by $1$ .

$y = \frac{3 x}{4} + \frac{- 15}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$y = \frac{3 x}{4} - \frac{15}{4}$