Solve for y 5-3(x+1)=2y-3x+2

$5 - 3 (x + 1) = 2 y - 3 x + 2$

Rewrite the equation as $2 y - 3 x + 2 = 5 - 3 (x + 1)$ .

$2 y - 3 x + 2 = 5 - 3 (x + 1)$

Simplify $5 - 3 (x + 1)$ .

Simplify each term.

Apply the distributive property.

$2 y - 3 x + 2 = 5 - 3 x - 3 \cdot 1$

Multiply $- 3$ by $1$ .

$2 y - 3 x + 2 = 5 - 3 x - 3$

Subtract $3$ from $5$ .

$2 y - 3 x + 2 = - 3 x + 2$

Move all terms not containing $y$ to the right side of the equation.

Add $3 x$ to both sides of the equation.

$2 y + 2 = - 3 x + 2 + 3 x$

Subtract $2$ from both sides of the equation.

$2 y = - 3 x + 2 + 3 x - 2$

Combine the opposite terms in $- 3 x + 2 + 3 x - 2$ .

Add $- 3 x$ and $3 x$ .

$2 y = 0 + 2 - 2$

Add $0$ and $2$ .

$2 y = 2 - 2$

Subtract $2$ from $2$ .

$2 y = 0$

Divide each term in $2 y = 0$ by $2$ and simplify.

Divide each term in $2 y = 0$ by $2$ .

$\frac{2 y}{2} = \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{0}{2}$

Divide $y$ by $1$ .

$y = \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

$y = 0$