Solve for y 5x+8y=40

$5 x + 8 y = 40$

Step 1

Subtract $5 x$ from both sides of the equation.

$8 y = 40 - 5 x$

Step 2

Divide each term in $8 y = 40 - 5 x$ by $8$ and simplify.

Divide each term in $8 y = 40 - 5 x$ by $8$ .

$\frac{8 y}{8} = \frac{40}{8} + \frac{- 5 x}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} = \frac{40}{8} + \frac{- 5 x}{8}$

Divide $y$ by $1$ .

$y = \frac{40}{8} + \frac{- 5 x}{8}$

Simplify the right side.

Simplify each term.

Divide $40$ by $8$ .

$y = 5 + \frac{- 5 x}{8}$

Move the negative in front of the fraction.

$y = 5 - \frac{5 x}{8}$