Solve for y 5x-8y=40 ; for y

$5 x - 8 y = 40$ ; for $y$

Subtract $5 x$ from both sides of the equation.

$- 8 y = 40 - 5 x$

Divide each term in $- 8 y = 40 - 5 x$ by $- 8$ and simplify.

Divide each term in $- 8 y = 40 - 5 x$ by $- 8$ .

$\frac{- 8 y}{- 8} = \frac{40}{- 8} + \frac{- 5 x}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 y}{- 8} = \frac{40}{- 8} + \frac{- 5 x}{- 8}$

Divide $y$ by $1$ .

$y = \frac{40}{- 8} + \frac{- 5 x}{- 8}$

Simplify the right side.

Simplify each term.

Divide $40$ by $- 8$ .

$y = - 5 + \frac{- 5 x}{- 8}$

Dividing two negative values results in a positive value.

$y = - 5 + \frac{5 x}{8}$