Solve for y 5x-y=1/4

$5 x - y = \frac{1}{4}$

Subtract $5 x$ from both sides of the equation.

$- y = \frac{1}{4} - 5 x$

Divide each term in $- y = \frac{1}{4} - 5 x$ by $- 1$ and simplify.

Divide each term in $- y = \frac{1}{4} - 5 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{\frac{1}{4}}{- 1} + \frac{- 5 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{\frac{1}{4}}{- 1} + \frac{- 5 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{\frac{1}{4}}{- 1} + \frac{- 5 x}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{\frac{1}{4}}{- 1}$ .

$y = - 1 \cdot \frac{1}{4} + \frac{- 5 x}{- 1}$

Rewrite $- 1 \cdot \frac{1}{4}$ as $- \frac{1}{4}$ .

$y = - \frac{1}{4} + \frac{- 5 x}{- 1}$

Move the negative one from the denominator of $\frac{- 5 x}{- 1}$ .

$y = - \frac{1}{4} - 1 \cdot (- 5 x)$

Rewrite $- 1 \cdot (- 5 x)$ as $- (- 5 x)$ .

$y = - \frac{1}{4} - (- 5 x)$

Multiply $- 5$ by $- 1$ .

$y = - \frac{1}{4} + 5 x$