Solve for y 6(2y-4)=0

$6 (2 y - 4) = 0$

Step 1

Divide each term in $6 (2 y - 4) = 0$ by $6$ and simplify.

Divide each term in $6 (2 y - 4) = 0$ by $6$ .

$\frac{6 (2 y - 4)}{6} = \frac{0}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 (2 y - 4)}{6} = \frac{0}{6}$

Divide $2 y - 4$ by $1$ .

$2 y - 4 = \frac{0}{6}$

Simplify the right side.

Divide $0$ by $6$ .

$2 y - 4 = 0$

Step 2

Add $4$ to both sides of the equation.

$2 y = 4$

Step 3

Divide each term in $2 y = 4$ by $2$ and simplify.

Divide each term in $2 y = 4$ by $2$ .

$\frac{2 y}{2} = \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{4}{2}$

Divide $y$ by $1$ .

$y = \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$y = 2$