Solve for y (6x)-(4y)=-10

$(6 \cdot x) - (4 \cdot y) = - 10$

Step 1

Multiply $- 1$ by $4$ .

$6 x - 4 y = - 10$

Step 2

Subtract $6 x$ from both sides of the equation.

$- 4 y = - 10 - 6 x$

Step 3

Divide each term in $- 4 y = - 10 - 6 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 10 - 6 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 10}{- 4} + \frac{- 6 x}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 10}{- 4} + \frac{- 6 x}{- 4}$

Divide $y$ by $1$ .

$y = \frac{- 10}{- 4} + \frac{- 6 x}{- 4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 10$ and $- 4$ .

Factor $- 2$ out of $- 10$ .

$y = \frac{- 2 (5)}{- 4} + \frac{- 6 x}{- 4}$

Cancel the common factors.

Factor $- 2$ out of $- 4$ .

$y = \frac{- 2 \cdot 5}{- 2 \cdot 2} + \frac{- 6 x}{- 4}$

Cancel the common factor.

$y = \frac{- 2 \cdot 5}{- 2 \cdot 2} + \frac{- 6 x}{- 4}$

Rewrite the expression.

$y = \frac{5}{2} + \frac{- 6 x}{- 4}$

Cancel the common factor of $- 6$ and $- 4$ .

Factor $- 2$ out of $- 6 x$ .

$y = \frac{5}{2} + \frac{- 2 (3 x)}{- 4}$

Cancel the common factors.

Factor $- 2$ out of $- 4$ .

$y = \frac{5}{2} + \frac{- 2 (3 x)}{- 2 (2)}$

Cancel the common factor.

$y = \frac{5}{2} + \frac{- 2 (3 x)}{- 2 \cdot 2}$

Rewrite the expression.

$y = \frac{5}{2} + \frac{3 x}{2}$

Solve for y (6*x)-(4*y)=-10