Solve for y 6(y+1)-10=4(y-1)+2y

$6 (y + 1) - 10 = 4 (y - 1) + 2 y$

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 (y - 1) + 2 y = 6 (y + 1) - 10$

Simplify $4 (y - 1) + 2 y$ .

Simplify each term.

Apply the distributive property.

$4 y + 4 \cdot - 1 + 2 y = 6 (y + 1) - 10$

Multiply $4$ by $- 1$ .

$4 y - 4 + 2 y = 6 (y + 1) - 10$

Add $4 y$ and $2 y$ .

$6 y - 4 = 6 (y + 1) - 10$

Simplify $6 (y + 1) - 10$ .

Simplify each term.

Apply the distributive property.

$6 y - 4 = 6 y + 6 \cdot 1 - 10$

Multiply $6$ by $1$ .

$6 y - 4 = 6 y + 6 - 10$

Subtract $10$ from $6$ .

$6 y - 4 = 6 y - 4$

Move all terms containing $y$ to the left side of the equation.

Subtract $6 y$ from both sides of the equation.

$6 y - 4 - 6 y = - 4$

Combine the opposite terms in $6 y - 4 - 6 y$ .

Subtract $6 y$ from $6 y$ .

$0 - 4 = - 4$

Subtract $4$ from $0$ .

$- 4 = - 4$

Since $- 4 = - 4$ , the equation will always be true for any value of $y$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$