Solve for y 6x-3y=12 for y

$6 x - 3 y = 12$ for $y$

Step 1

Subtract $6 x$ from both sides of the equation.

$- 3 y = 12 - 6 x$

Step 2

Divide each term in $- 3 y = 12 - 6 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 12 - 6 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{12}{- 3} + \frac{- 6 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{12}{- 3} + \frac{- 6 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{12}{- 3} + \frac{- 6 x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $12$ by $- 3$ .

$y = - 4 + \frac{- 6 x}{- 3}$

Cancel the common factor of $- 6$ and $- 3$ .

Factor $- 3$ out of $- 6 x$ .

$y = - 4 + \frac{- 3 (2 x)}{- 3}$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = - 4 + \frac{- 3 (2 x)}{- 3 (1)}$

Cancel the common factor.

$y = - 4 + \frac{- 3 (2 x)}{- 3 \cdot 1}$

Rewrite the expression.

$y = - 4 + \frac{2 x}{1}$

Divide $2 x$ by $1$ .

$y = - 4 + 2 x$