Solve for y 6x+3y=15

$6 x + 3 y = 15$

Step 1

Subtract $6 x$ from both sides of the equation.

$3 y = 15 - 6 x$

Step 2

Divide each term in $3 y = 15 - 6 x$ by $3$ and simplify.

Divide each term in $3 y = 15 - 6 x$ by $3$ .

$\frac{3 y}{3} = \frac{15}{3} + \frac{- 6 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{15}{3} + \frac{- 6 x}{3}$

Divide $y$ by $1$ .

$y = \frac{15}{3} + \frac{- 6 x}{3}$

$y = \frac{15}{3} + \frac{- 6 x}{3}$

$y = \frac{15}{3} + \frac{- 6 x}{3}$

Simplify the right side.

Simplify each term.

Divide $15$ by $3$ .

$y = 5 + \frac{- 6 x}{3}$

Cancel the common factor of $- 6$ and $3$ .

Factor $3$ out of $- 6 x$ .

$y = 5 + \frac{3 (- 2 x)}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$y = 5 + \frac{3 (- 2 x)}{3 (1)}$

Cancel the common factor.

$y = 5 + \frac{3 (- 2 x)}{3 \cdot 1}$

Rewrite the expression.

$y = 5 + \frac{- 2 x}{1}$

Divide $- 2 x$ by $1$ .

$y = 5 - 2 x$

$y = 5 - 2 x$

$y = 5 - 2 x$

$y = 5 - 2 x$

$y = 5 - 2 x$

$y = 5 - 2 x$

Related Questions