Solve for y -6y+13+9y=8y-3

$- 6 y + 13 + 9 y = 8 y - 3$

Step 1

Add $- 6 y$ and $9 y$ .

$3 y + 13 = 8 y - 3$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $8 y$ from both sides of the equation.

$3 y + 13 - 8 y = - 3$

Subtract $8 y$ from $3 y$ .

$- 5 y + 13 = - 3$

Step 3

Move all terms not containing $y$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$- 5 y = - 3 - 13$

Subtract $13$ from $- 3$ .

$- 5 y = - 16$

Step 4

Divide each term in $- 5 y = - 16$ by $- 5$ and simplify.

Divide each term in $- 5 y = - 16$ by $- 5$ .

$\frac{- 5 y}{- 5} = \frac{- 16}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 y}{- 5} = \frac{- 16}{- 5}$

Divide $y$ by $1$ .

$y = \frac{- 16}{- 5}$

Simplify the right side.

Dividing two negative values results in a positive value.

$y = \frac{16}{5}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$y = \frac{16}{5}$

Decimal Form:

$y = 3.2$

Mixed Number Form:

$y = 3 \frac{1}{5}$