Solve for y 7(y+2)-(4y-10)=44-2y+5

$7 (y + 2) - (4 y - 10) = 44 - 2 y + 5$

Step 1

Simplify $7 (y + 2) - (4 y - 10)$ .

Simplify each term.

Apply the distributive property.

$7 y + 7 \cdot 2 - (4 y - 10) = 44 - 2 y + 5$

Multiply $7$ by $2$ .

$7 y + 14 - (4 y - 10) = 44 - 2 y + 5$

Apply the distributive property.

$7 y + 14 - (4 y) - - 10 = 44 - 2 y + 5$

Multiply $4$ by $- 1$ .

$7 y + 14 - 4 y - - 10 = 44 - 2 y + 5$

Multiply $- 1$ by $- 10$ .

$7 y + 14 - 4 y + 10 = 44 - 2 y + 5$

Simplify by adding terms.

Subtract $4 y$ from $7 y$ .

$3 y + 14 + 10 = 44 - 2 y + 5$

Add $14$ and $10$ .

$3 y + 24 = 44 - 2 y + 5$

Step 2

Add $44$ and $5$ .

$3 y + 24 = - 2 y + 49$

Step 3

Move all terms containing $y$ to the left side of the equation.

Add $2 y$ to both sides of the equation.

$3 y + 24 + 2 y = 49$

Add $3 y$ and $2 y$ .

$5 y + 24 = 49$

Step 4

Move all terms not containing $y$ to the right side of the equation.

Subtract $24$ from both sides of the equation.

$5 y = 49 - 24$

Subtract $24$ from $49$ .

$5 y = 25$

Step 5

Divide each term in $5 y = 25$ by $5$ and simplify.

Divide each term in $5 y = 25$ by $5$ .

$\frac{5 y}{5} = \frac{25}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 y}{5} = \frac{25}{5}$

Divide $y$ by $1$ .

$y = \frac{25}{5}$

Simplify the right side.

Divide $25$ by $5$ .

$y = 5$

Solve for y 7(y+2)-(4y-10)=44-2y+5

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