Solve for y (8+2y)/3=x

$\frac{8 + 2 y}{3} = x$

Multiply both sides by $3$ .

$\frac{8 + 2 y}{3} \cdot 3 = x \cdot 3$

Simplify.

Simplify the left side.

Simplify $\frac{8 + 2 y}{3} \cdot 3$ .

Factor $2$ out of $8 + 2 y$ .

Factor $2$ out of $8$ .

$\frac{2 \cdot 4 + 2 y}{3} \cdot 3 = x \cdot 3$

Factor $2$ out of $2 \cdot 4 + 2 y$ .

$\frac{2 (4 + y)}{3} \cdot 3 = x \cdot 3$

$\frac{2 (4 + y)}{3} \cdot 3 = x \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{2 (4 + y)}{3} \cdot 3 = x \cdot 3$

Rewrite the expression.

$2 (4 + y) = x \cdot 3$

$2 (4 + y) = x \cdot 3$

Apply the distributive property.

$2 \cdot 4 + 2 y = x \cdot 3$

Simplify the expression.

Multiply $2$ by $4$ .

$8 + 2 y = x \cdot 3$

Reorder $8$ and $2 y$ .

$2 y + 8 = x \cdot 3$

$2 y + 8 = x \cdot 3$

$2 y + 8 = x \cdot 3$

$2 y + 8 = x \cdot 3$

Simplify the right side.

Move $3$ to the left of $x$ .

$2 y + 8 = 3 x$

$2 y + 8 = 3 x$

$2 y + 8 = 3 x$

Solve for $y$ .

Subtract $8$ from both sides of the equation.

$2 y = 3 x - 8$

Divide each term in $2 y = 3 x - 8$ by $2$ and simplify.

Divide each term in $2 y = 3 x - 8$ by $2$ .

$\frac{2 y}{2} = \frac{3 x}{2} + \frac{- 8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{3 x}{2} + \frac{- 8}{2}$

Divide $y$ by $1$ .

$y = \frac{3 x}{2} + \frac{- 8}{2}$

$y = \frac{3 x}{2} + \frac{- 8}{2}$

$y = \frac{3 x}{2} + \frac{- 8}{2}$

Simplify the right side.

Divide $- 8$ by $2$ .

$y = \frac{3 x}{2} - 4$

$y = \frac{3 x}{2} - 4$

$y = \frac{3 x}{2} - 4$

$y = \frac{3 x}{2} - 4$

Related Questions