Solve for y 8(5y+x)=4

$8 (5 y + x) = 4$

Step 1

Divide each term in $8 (5 y + x) = 4$ by $8$ and simplify.

Divide each term in $8 (5 y + x) = 4$ by $8$ .

$\frac{8 (5 y + x)}{8} = \frac{4}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 (5 y + x)}{8} = \frac{4}{8}$

Divide $5 y + x$ by $1$ .

$5 y + x = \frac{4}{8}$

Simplify the right side.

Cancel the common factor of $4$ and $8$ .

Factor $4$ out of $4$ .

$5 y + x = \frac{4 (1)}{8}$

Cancel the common factors.

Factor $4$ out of $8$ .

$5 y + x = \frac{4 \cdot 1}{4 \cdot 2}$

Cancel the common factor.

$5 y + x = \frac{4 \cdot 1}{4 \cdot 2}$

Rewrite the expression.

$5 y + x = \frac{1}{2}$

Step 2

Subtract $x$ from both sides of the equation.

$5 y = \frac{1}{2} - x$

Step 3

Divide each term in $5 y = \frac{1}{2} - x$ by $5$ and simplify.

Divide each term in $5 y = \frac{1}{2} - x$ by $5$ .

$\frac{5 y}{5} = \frac{\frac{1}{2}}{5} + \frac{- x}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 y}{5} = \frac{\frac{1}{2}}{5} + \frac{- x}{5}$

Divide $y$ by $1$ .

$y = \frac{\frac{1}{2}}{5} + \frac{- x}{5}$

Simplify the right side.

Simplify each term.

Multiply the numerator by the reciprocal of the denominator.

$y = \frac{1}{2} \cdot \frac{1}{5} + \frac{- x}{5}$

Multiply $\frac{1}{2} \cdot \frac{1}{5}$ .

Multiply $\frac{1}{2}$ by $\frac{1}{5}$ .

$y = \frac{1}{2 \cdot 5} + \frac{- x}{5}$

Multiply $2$ by $5$ .

$y = \frac{1}{10} + \frac{- x}{5}$

Move the negative in front of the fraction.

$y = \frac{1}{10} - \frac{x}{5}$

Solve for y 8(5y+x)=4

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