Solve for y 8(y-2)=4y

$8 (y - 2) = 4 y$

Step 1

Simplify $8 (y - 2)$ .

Rewrite.

$0 + 0 + 8 (y - 2) = 4 y$

Simplify by adding zeros.

$8 (y - 2) = 4 y$

Apply the distributive property.

$8 y + 8 \cdot - 2 = 4 y$

Multiply $8$ by $- 2$ .

$8 y - 16 = 4 y$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $4 y$ from both sides of the equation.

$8 y - 16 - 4 y = 0$

Subtract $4 y$ from $8 y$ .

$4 y - 16 = 0$

Step 3

Add $16$ to both sides of the equation.

$4 y = 16$

Step 4

Divide each term in $4 y = 16$ by $4$ and simplify.

Divide each term in $4 y = 16$ by $4$ .

$\frac{4 y}{4} = \frac{16}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{16}{4}$

Divide $y$ by $1$ .

$y = \frac{16}{4}$

Simplify the right side.

Divide $16$ by $4$ .

$y = 4$