Solve for y 8x-3=5+4y

$8 x - 3 = 5 + 4 y$

Step 1

Rewrite the equation as $5 + 4 y = 8 x - 3$ .

$5 + 4 y = 8 x - 3$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$4 y = 8 x - 3 - 5$

Subtract $5$ from $- 3$ .

$4 y = 8 x - 8$

Step 3

Divide each term in $4 y = 8 x - 8$ by $4$ and simplify.

Divide each term in $4 y = 8 x - 8$ by $4$ .

$\frac{4 y}{4} = \frac{8 x}{4} + \frac{- 8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{8 x}{4} + \frac{- 8}{4}$

Divide $y$ by $1$ .

$y = \frac{8 x}{4} + \frac{- 8}{4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $8$ and $4$ .

Factor $4$ out of $8 x$ .

$y = \frac{4 (2 x)}{4} + \frac{- 8}{4}$

Cancel the common factors.

Factor $4$ out of $4$ .

$y = \frac{4 (2 x)}{4 (1)} + \frac{- 8}{4}$

Cancel the common factor.

$y = \frac{4 (2 x)}{4 \cdot 1} + \frac{- 8}{4}$

Rewrite the expression.

$y = \frac{2 x}{1} + \frac{- 8}{4}$

Divide $2 x$ by $1$ .

$y = 2 x + \frac{- 8}{4}$

Divide $- 8$ by $4$ .

$y = 2 x - 2$