Solve for y 8x-4y=12

$8 x - 4 y = 12$

Step 1

Subtract $8 x$ from both sides of the equation.

$- 4 y = 12 - 8 x$

Step 2

Divide each term in $- 4 y = 12 - 8 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = 12 - 8 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{12}{- 4} + \frac{- 8 x}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{12}{- 4} + \frac{- 8 x}{- 4}$

Divide $y$ by $1$ .

$y = \frac{12}{- 4} + \frac{- 8 x}{- 4}$

Simplify the right side.

Simplify each term.

Divide $12$ by $- 4$ .

$y = - 3 + \frac{- 8 x}{- 4}$

Cancel the common factor of $- 8$ and $- 4$ .

Factor $- 4$ out of $- 8 x$ .

$y = - 3 + \frac{- 4 (2 x)}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = - 3 + \frac{- 4 (2 x)}{- 4 (1)}$

Cancel the common factor.

$y = - 3 + \frac{- 4 (2 x)}{- 4 \cdot 1}$

Rewrite the expression.

$y = - 3 + \frac{2 x}{1}$

Divide $2 x$ by $1$ .

$y = - 3 + 2 x$