Solve for y 9+y^3=71

$9 + y^{3} = 71$

Move all terms not containing $y$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$y^{3} = 71 - 9$

Subtract $9$ from $71$ .

$y^{3} = 62$

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$y = \sqrt[3]{62}$

The result can be shown in multiple forms.

Exact Form:

$y = \sqrt[3]{62}$

Decimal Form:

$y = 3.95789160 \dots$