Solve for y x=3/4(y+z)

$x = \frac{3}{4} (y + z)$

Step 1

Rewrite the equation as $\frac{3}{4} \cdot (y + z) = x$ .

$\frac{3}{4} \cdot (y + z) = x$

Step 2

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} (\frac{3}{4} \cdot (y + z)) = \frac{4}{3} x$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} (\frac{3}{4} \cdot (y + z))$ .

Apply the distributive property.

$\frac{4}{3} (\frac{3}{4} y + \frac{3}{4} z) = \frac{4}{3} x$

Combine $\frac{3}{4}$ and $y$ .

$\frac{4}{3} (\frac{3 y}{4} + \frac{3}{4} z) = \frac{4}{3} x$

Combine $\frac{3}{4}$ and $z$ .

$\frac{4}{3} (\frac{3 y}{4} + \frac{3 z}{4}) = \frac{4}{3} x$

Apply the distributive property.

$\frac{4}{3} \cdot \frac{3 y}{4} + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{3} \cdot \frac{3 y}{4} + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Rewrite the expression.

$\frac{1}{3} (3 y) + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Cancel the common factor of $3$ .

Factor $3$ out of $3 y$ .

$\frac{1}{3} (3 (y)) + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Cancel the common factor.

$\frac{1}{3} (3 y) + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Rewrite the expression.

$y + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Cancel the common factor of $4$ .

Cancel the common factor.

$y + \frac{4}{3} \cdot \frac{3 z}{4} = \frac{4}{3} x$

Rewrite the expression.

$y + \frac{1}{3} (3 z) = \frac{4}{3} x$

Cancel the common factor of $3$ .

Factor $3$ out of $3 z$ .

$y + \frac{1}{3} (3 (z)) = \frac{4}{3} x$

Cancel the common factor.

$y + \frac{1}{3} (3 z) = \frac{4}{3} x$

Rewrite the expression.

$y + z = \frac{4}{3} x$

Simplify the right side.

Combine $\frac{4}{3}$ and $x$ .

$y + z = \frac{4 x}{3}$

Step 4

Subtract $z$ from both sides of the equation.

$y = \frac{4 x}{3} - z$

Solve for y x=3/4(y+z)

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