Solve for y x-3(y+2)=6

$x - 3 (y + 2) = 6$

Simplify each term.

Apply the distributive property.

$x - 3 y - 3 \cdot 2 = 6$

Multiply $- 3$ by $2$ .

$x - 3 y - 6 = 6$

Move all terms not containing $y$ to the right side of the equation.

Subtract $x$ from both sides of the equation.

$- 3 y - 6 = 6 - x$

Add $6$ to both sides of the equation.

$- 3 y = 6 - x + 6$

Add $6$ and $6$ .

$- 3 y = - x + 12$

Divide each term in $- 3 y = - x + 12$ by $- 3$ and simplify.

Divide each term in $- 3 y = - x + 12$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- x}{- 3} + \frac{12}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- x}{- 3} + \frac{12}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- x}{- 3} + \frac{12}{- 3}$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$y = \frac{x}{3} + \frac{12}{- 3}$

Divide $12$ by $- 3$ .

$y = \frac{x}{3} - 4$