Solve for y x=4/7(y+z)

$x = \frac{4}{7} (y + z)$

Step 1

Rewrite the equation as $\frac{4}{7} \cdot (y + z) = x$ .

$\frac{4}{7} \cdot (y + z) = x$

Step 2

Multiply both sides of the equation by $\frac{7}{4}$ .

$\frac{7}{4} (\frac{4}{7} \cdot (y + z)) = \frac{7}{4} x$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{7}{4} (\frac{4}{7} \cdot (y + z))$ .

Apply the distributive property.

$\frac{7}{4} (\frac{4}{7} y + \frac{4}{7} z) = \frac{7}{4} x$

Combine $\frac{4}{7}$ and $y$ .

$\frac{7}{4} (\frac{4 y}{7} + \frac{4}{7} z) = \frac{7}{4} x$

Combine $\frac{4}{7}$ and $z$ .

$\frac{7}{4} (\frac{4 y}{7} + \frac{4 z}{7}) = \frac{7}{4} x$

Apply the distributive property.

$\frac{7}{4} \cdot \frac{4 y}{7} + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7}{4} \cdot \frac{4 y}{7} + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Rewrite the expression.

$\frac{1}{4} (4 y) + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Cancel the common factor of $4$ .

Factor $4$ out of $4 y$ .

$\frac{1}{4} (4 (y)) + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Cancel the common factor.

$\frac{1}{4} (4 y) + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Rewrite the expression.

$y + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Cancel the common factor of $7$ .

Cancel the common factor.

$y + \frac{7}{4} \cdot \frac{4 z}{7} = \frac{7}{4} x$

Rewrite the expression.

$y + \frac{1}{4} (4 z) = \frac{7}{4} x$

Cancel the common factor of $4$ .

Factor $4$ out of $4 z$ .

$y + \frac{1}{4} (4 (z)) = \frac{7}{4} x$

Cancel the common factor.

$y + \frac{1}{4} (4 z) = \frac{7}{4} x$

Rewrite the expression.

$y + z = \frac{7}{4} x$

Simplify the right side.

Combine $\frac{7}{4}$ and $x$ .

$y + z = \frac{7 x}{4}$

Step 4

Subtract $z$ from both sides of the equation.

$y = \frac{7 x}{4} - z$

Solve for y x=4/7(y+z)

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