Solve for y y+2=1/6(x-0)

$y + 2 = \frac{1}{6} (x - 0)$

Step 1

Simplify $\frac{1}{6} \cdot (x - 0)$ .

Rewrite.

$y + 2 = 0 + 0 + \frac{1}{6} \cdot (x - 0)$

Subtract $0$ from $x$ .

$y + 2 = \frac{1}{6} \cdot x$

Combine $\frac{1}{6}$ and $x$ .

$y + 2 = \frac{x}{6}$

$y + 2 = \frac{x}{6}$

Step 2

Subtract $2$ from both sides of the equation.

$y = \frac{x}{6} - 2$

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