Solve for y y=2(4)^-2

$y = 2 {(4)}^{- 2}$

Remove parentheses.

$y = 2 \cdot 4^{- 2}$

Simplify $2 \cdot 4^{- 2}$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y = 2 \cdot \frac{1}{4^{2}}$

Raise $4$ to the power of $2$ .

$y = 2 \cdot \frac{1}{16}$

Cancel the common factor of $2$ .

Factor $2$ out of $16$ .

$y = 2 \cdot \frac{1}{2 (8)}$

Cancel the common factor.

$y = 2 \cdot \frac{1}{2 \cdot 8}$

Rewrite the expression.

$y = \frac{1}{8}$

The result can be shown in multiple forms.

Exact Form:

$y = \frac{1}{8}$

Decimal Form:

$y = 0.125$