Solve for y -y/3+19=33

$- \frac{y}{3} + 19 = 33$

Move all terms not containing $y$ to the right side of the equation.

Subtract $19$ from both sides of the equation.

$- \frac{y}{3} = 33 - 19$

Subtract $19$ from $33$ .

$- \frac{y}{3} = 14$

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{y}{3}) = - 3 \cdot 14$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 (- \frac{y}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{y}{3}$ into the numerator.

$- 3 \frac{- y}{3} = - 3 \cdot 14$

Factor $3$ out of $- 3$ .

$3 (- 1) \frac{- y}{3} = - 3 \cdot 14$

Cancel the common factor.

$3 \cdot - 1 \frac{- y}{3} = - 3 \cdot 14$

Rewrite the expression.

$- - y = - 3 \cdot 14$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 y = - 3 \cdot 14$

Multiply $y$ by $1$ .

$y = - 3 \cdot 14$

Simplify the right side.

Multiply $- 3$ by $14$ .

$y = - 42$