Solve for y y+3/8>16

$y + \frac{3}{8} > 16$

Step 1

Subtract $\frac{3}{8}$ from both sides of the inequality.

$y > 16 - \frac{3}{8}$

Step 2

To write $16$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$y > 16 \cdot \frac{8}{8} - \frac{3}{8}$

Step 3

Combine $16$ and $\frac{8}{8}$ .

$y > \frac{16 \cdot 8}{8} - \frac{3}{8}$

Step 4

Combine the numerators over the common denominator.

$y > \frac{16 \cdot 8 - 3}{8}$

Step 5

Simplify the numerator.

Multiply $16$ by $8$ .

$y > \frac{128 - 3}{8}$

Subtract $3$ from $128$ .

$y > \frac{125}{8}$

Step 6

The result can be shown in multiple forms.

Inequality Form:

$y > \frac{125}{8}$

Interval Notation:

$(\frac{125}{8}, \infty)$