Solve for y (y+3)/(y-1)=4/(y-1)

$\frac{y + 3}{y - 1} = \frac{4}{y - 1}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$y + 3 = 4$

Move all terms not containing $y$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$y = 4 - 3$

Subtract $3$ from $4$ .

$y = 1$

Exclude the solutions that do not make $\frac{y + 3}{y - 1} = \frac{4}{y - 1}$ true.

$No solution$