Solve for y y-5=3-9(y+2)

$y - 5 = 3 - 9 (y + 2)$

Simplify $3 - 9 (y + 2)$ .

Simplify each term.

Apply the distributive property.

$y - 5 = 3 - 9 y - 9 \cdot 2$

Multiply $- 9$ by $2$ .

$y - 5 = 3 - 9 y - 18$

Subtract $18$ from $3$ .

$y - 5 = - 9 y - 15$

Move all terms containing $y$ to the left side of the equation.

Add $9 y$ to both sides of the equation.

$y - 5 + 9 y = - 15$

Add $y$ and $9 y$ .

$10 y - 5 = - 15$

Move all terms not containing $y$ to the right side of the equation.

Add $5$ to both sides of the equation.

$10 y = - 15 + 5$

Add $- 15$ and $5$ .

$10 y = - 10$

Divide each term in $10 y = - 10$ by $10$ and simplify.

Divide each term in $10 y = - 10$ by $10$ .

$\frac{10 y}{10} = \frac{- 10}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 y}{10} = \frac{- 10}{10}$

Divide $y$ by $1$ .

$y = \frac{- 10}{10}$

Simplify the right side.

Divide $- 10$ by $10$ .

$y = - 1$