Solve for y y^5=32

$y^{5} = 32$

Take the 5th root of both sides of the equation to eliminate the exponent on the left side.

$y = \sqrt[5]{32}$

Simplify $\sqrt[5]{32}$ .

Rewrite $32$ as $2^{5}$ .

$y = \sqrt[5]{2^{5}}$

Pull terms out from under the radical, assuming real numbers.

$y = 2$