Solve for y y = square root of 64-6

$y = \sqrt{64} - 6$

Step 1

Simplify each term.

Rewrite $64$ as $8^{2}$ .

$y = \sqrt{8^{2}} - 6$

Pull terms out from under the radical, assuming positive real numbers.

$y = 8 - 6$

Step 2

Subtract $6$ from $8$ .

$y = 2$