Solve for y y-x=16 x=12

$y - x = 16$ $x = 12$

Replace all occurrences of $x$ with $12$ in each equation.

Replace all occurrences of $x$ in $y - x = 16$ with $12$ .

$y - (12) = 16$

$x = 12$

Simplify the left side.

Multiply $- 1$ by $12$ .

$y - 12 = 16$

$x = 12$

$y - 12 = 16$

$x = 12$

$y - 12 = 16$

$x = 12$

The simplified system is the arbitrary solution of the original system of equations.

$y = 28$

$x = 12$