Solve for y2 ((y_1-y_2)x)/3=B

$\frac{(y_{1} - y_{2}) x}{3} = B$

Step 1

Multiply both sides by $3$ .

$\frac{(y_{1} - y_{2}) x}{3} \cdot 3 = B \cdot 3$

Step 2

Simplify.

Simplify the left side.

Simplify $\frac{(y_{1} - y_{2}) x}{3} \cdot 3$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{(y_{1} - y_{2}) x}{3} \cdot 3 = B \cdot 3$

Rewrite the expression.

$(y_{1} - y_{2}) x = B \cdot 3$

Apply the distributive property.

$y_{1} x - y_{2} x = B \cdot 3$

Simplify the expression.

Reorder $y_{1}$ and $x$ .

$x y_{1} - y_{2} x = B \cdot 3$

Move $y_{2}$ .

$x y_{1} - 1 x y_{2} = B \cdot 3$

Simplify the right side.

Move $3$ to the left of $B$ .

$x y_{1} - 1 x y_{2} = 3 B$

Step 3

Solve for $y_{1}$ .

Rewrite $- 1 x$ as $- x$ .

$x y_{1} - x y_{2} = 3 B$

Add $x y_{2}$ to both sides of the equation.

$x y_{1} = 3 B + x y_{2}$

Divide each term in $x y_{1} = 3 B + x y_{2}$ by $x$ and simplify.

Divide each term in $x y_{1} = 3 B + x y_{2}$ by $x$ .

$\frac{x y_{1}}{x} = \frac{3 B}{x} + \frac{x y_{2}}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{x y_{1}}{x} = \frac{3 B}{x} + \frac{x y_{2}}{x}$

Divide $y_{1}$ by $1$ .

$y_{1} = \frac{3 B}{x} + \frac{x y_{2}}{x}$

Simplify the right side.

Cancel the common factor of $x$ .

Cancel the common factor.

$y_{1} = \frac{3 B}{x} + \frac{x y_{2}}{x}$

Divide $y_{2}$ by $1$ .

$y_{1} = \frac{3 B}{x} + y_{2}$