Solve for z 12=15(z-1/5)

$12 = 15 (z - \frac{1}{5})$

Rewrite the equation as $15 (z - \frac{1}{5}) = 12$ .

$15 (z - \frac{1}{5}) = 12$

Simplify.

Apply the distributive property.

$15 z + 15 (- \frac{1}{5}) = 12$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{1}{5}$ into the numerator.

$15 z + 15 (\frac{- 1}{5}) = 12$

Factor $5$ out of $15$ .

$15 z + 5 (3) \frac{- 1}{5} = 12$

Cancel the common factor.

$15 z + 5 \cdot 3 \frac{- 1}{5} = 12$

Rewrite the expression.

$15 z + 3 \cdot - 1 = 12$

Multiply $3$ by $- 1$ .

$15 z - 3 = 12$

Divide each term in $(15 z - 3) = 12$ by $15$ and simplify.

Divide each term in $(15 z - 3) = 12$ by $15$ .

$\frac{(15 z - 3)}{15} = \frac{12}{15}$

Simplify the left side.

Cancel the common factor of $15 z - 3$ and $15$ .

Factor $3$ out of $15 z$ .

$\frac{3 (5 z) - 3}{15} = \frac{12}{15}$

Factor $3$ out of $- 3$ .

$\frac{3 (5 z) + 3 (- 1)}{15} = \frac{12}{15}$

Factor $3$ out of $3 (5 z) + 3 (- 1)$ .

$\frac{3 (5 z - 1)}{15} = \frac{12}{15}$

Cancel the common factors.

Factor $3$ out of $15$ .

$\frac{3 (5 z - 1)}{3 (5)} = \frac{12}{15}$

Cancel the common factor.

$\frac{3 (5 z - 1)}{3 \cdot 5} = \frac{12}{15}$

Rewrite the expression.

$\frac{5 z - 1}{5} = \frac{12}{15}$

Simplify the right side.

Cancel the common factor of $12$ and $15$ .

Factor $3$ out of $12$ .

$\frac{5 z - 1}{5} = \frac{3 (4)}{15}$

Cancel the common factors.

Factor $3$ out of $15$ .

$\frac{5 z - 1}{5} = \frac{3 \cdot 4}{3 \cdot 5}$

Cancel the common factor.

$\frac{5 z - 1}{5} = \frac{3 \cdot 4}{3 \cdot 5}$

Rewrite the expression.

$\frac{5 z - 1}{5} = \frac{4}{5}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$5 z - 1 = 4$

Move all terms not containing $z$ to the right side of the equation.

Add $1$ to both sides of the equation.

$5 z = 4 + 1$

Add $4$ and $1$ .

$5 z = 5$

Divide each term in $5 z = 5$ by $5$ and simplify.

Divide each term in $5 z = 5$ by $5$ .

$\frac{5 z}{5} = \frac{5}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 z}{5} = \frac{5}{5}$

Divide $z$ by $1$ .

$z = \frac{5}{5}$

Simplify the right side.

Divide $5$ by $5$ .

$z = 1$

Solve for z 12=15(z-1/5)

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